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  4. A thermos flask contains 250 g of coffee at 90° C. To this 20 g of milk at 5° C is added. After equilibrium is established, the temperature of the liquid is (Assume no heat loss to the thermos bottle. Take specific heat of coffee and milk as 1.00 cal / g° C)

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Q. A thermos flask contains $250 \,g$ of coffee at $90^{\circ}\, C$. To this $20\, g$ of milk at $5^{\circ} \,C$ is added. After equilibrium is established, the temperature of the liquid is
(Assume no heat loss to the thermos bottle. Take specific heat of coffee and milk as $1.00\, cal / g^{\circ}\, C$)

TS EAMCET 2015

Solution:

Let after getting equilibrium stage final temperature is $T$.
Then, according to loss of calorimetry
Heat loss $=$ Heat gain
$\Rightarrow (250)(1)(90-T)=20(1)(T-5)$
$\Rightarrow T=83.7^{\circ} C$