1. Tardigrade
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  3. Physics
  4. A thermometer has wrong calibration (of course at equal distances and the capillary is of uniform diameter). It reads the melting point of ice as -10° C. It reads 60° C in place of 50°. The temperature of boiling point of water on this scale is :

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Q. A thermometer has wrong calibration (of course at equal distances and the capillary is of uniform diameter). It reads the melting point of ice as $-10^{\circ} C$. It reads $60^{\circ} C$ in place of $50^{\circ}$. The temperature of boiling point of water on this scale is :

Thermal Properties of Matter

Solution:

We use
$\frac{\text { Reading of faulty thermometer }-L F P}{U F P-L F P}=\frac{C-0}{100}$
$\Rightarrow \frac{60-(-10)}{U-(10)}=\frac{50}{100}$
$\Rightarrow U=130^{\circ} C$