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Physics
A thermodynamical system undergoes cyclic process ABCDA as shown in the figure. Work done by the system is <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-yvaguzepvc9hyvas.jpg />
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Q. A thermodynamical system undergoes cyclic process $ABCDA$ as shown in the figure. Work done by the system is
NTA Abhyas
NTA Abhyas 2022
A
Zero
B
$2P_{0}V_{0}$
C
$P_{0}V_{0}$
D
$\frac{3}{2}P_{0}V_{0}$
Solution:
As can be seen from figure,
$\text{W}_{\text{BCOB}} = - \text{area of} \Delta \text{BCO} = - \frac{\text{P}_{0} \text{V}_{0}}{2}$
$\text{W}_{\text{AODA}} = + \text{area of} \Delta \text{AOD} = + \frac{\text{P}_{0} \text{V}_{0}}{2}$
$\therefore \text{W}_{\text{net}} = \text{W}_{\text{BCOB}} + \text{W}_{\text{AODA}} = - \frac{\text{P}_{0} \text{V}_{0}}{2} + \frac{\text{P}_{0} \text{V}_{0}}{2} = \text{zero}$
