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Q. A ten fold increase in the $ [H^+] $ of a solution

AMUAMU 2012Equilibrium

Solution:

$pH_1 = - log[H_1^+]$
$pH_2 = - log[10H_1^+]$
$ = - log [H^+] - log \,10$
$ = - log \,[H^+] - 1$
$ = pH_1 - 1$