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  4. A telescope consisting of an objective of focal length 60 cm and a single eye lens of focal length 20 cm is focused on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends at angle of 1° at objective, the angular width of image is

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Q. A telescope consisting of an objective of focal length $60 \,cm$ and a single eye lens of focal length $20 \,cm$ is focused on a distant object in such a way that parallel rays comes out from the eye lens. If the object subtends at angle of $1^{\circ}$ at objective, the angular width of image is

Solution:

$m=\frac{\theta}{\theta_{0}}=\frac{f_{0}}{f_{e}} $
$\Rightarrow \theta=1^{\circ} \times \frac{60}{20}=3^{\circ}$