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Q. A tap supplies water at 22$^{\circ}$ C, a man takes J L of water per min at 37$^{\circ}$ C from the geyser. The power of the geyser is

Work, Energy and Power

Solution:

Power, P = $\frac{ W }{ t } = \frac{ m \times s \times \triangle t }{ t } $
= $ \frac{ 1 \times 4200 \times ( 37 - 22)}{ 60 } $
= 1050 W