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Chemistry
A system absorbs 600 J o f heat and work equivalent to 300 J on its surroundings. The change in internal energy is:
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Q. A system absorbs $600 J$ o f heat and work equivalent to $300 J$ on its surroundings. The change in internal energy is:
Thermodynamics
A
$300\, J$
83%
B
$400\, J$
6%
C
$500\, J$
5%
D
$600\, J$
5%
Solution:
We know that $\Delta E=Q + W= 600 + (-300) = 300 J$
$W= - 300,$ because the work is done by the system