Question

A symmetrical form of the line of intersection of the planes $x = ay + b$ and $z = cy + d$ is :

• A. $\frac{x-b}{a}=\frac{y-1}{1}=\frac{z-d}{c}$
• B. $\frac{x-b-a}{a}=\frac{y-1}{1}=\frac{z-d-c}{c}$
• C. $\frac{x-a}{b}=\frac{y-0}{1}=\frac{z-c}{d}$
• D. $\frac{x-b-a}{b}=\frac{y-1}{0}=\frac{z-d-c}{d}$

Answer 1

Answer: (B)

$\frac{x-b}{a}=y=\frac{z-d}{c}$
$\Rightarrow \frac{x-b}{a}-1=y-1=\frac{z-d}{c}-1$
$\frac{x-b-a}{a}=\frac{y-1}{1}=\frac{z-d-c}{c}$