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Q. A swimming team has eight members, only two of which are boys. The coach wants to take a delegation from the team to a special swimming camp. If the delegation must have either five or six members, and must include atleast one boy, then the number of ways to select the delegation, is

Permutations and Combinations

Solution:

METHOD - 1
CASE - 1 : Delegation consists of $5$ members
(a) $1$ Boy $+4$ Girls ${ }^{2} C _{1} \times{ }^{6} C _{4}=30$
(b) $2$ Boys $+3$ Girls ${ }^{2} C _{2} \times{ }^{6} C _{3}=20$
$50$
CASE - 2 : Delegation consists of $6$ members
(a) $1$ Boy $+5$ Girls ${ }^{2} C _{1} \times{ }^{6} C _{5}=12$
(b) $2$ Boys $+4$ Girls $2 C 2 \times{ }^{6} C _{4}=15$
$77$ ways
METHOD-2
CASE - 1 : Delegation consists of $5$ members
Total number of ways of selecting $5$ member team number of ways when no boy is selected
$={ }^{8} C _{5}-{ }^{6} C _{5}=50$
CASE - 2 : Delegation consists of 6 members
$\therefore $ Total - no, boy is selected
$={ }^{8} C _{6}-{ }^{6} C _{6}=27 $
Total $=50 +27=77$