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Q.
A survey shows that $63 \%$ of the people in a city read newspaper A whereas $76 \%$ read newspaper $B$. If $x \%$ of the people read both the newspapers, then a possible value of $x$ can be:
Finding the value of $x$ :
Let the people read news $A$ is $n(A)=63 \%$
the people read news $B$ is $n(B)=76 \%$
the people read both the newspapers $n(A \cap B)=x$
We know that $\max (n(A) \& n(B)) \leq n(A \cup B) \leq 100$
$
\Rightarrow 76 \leq 63+76-x \leq 100 $
$\Rightarrow-63 \leq-x \leq-39 $
$\Rightarrow 63 \geq x \geq 39$