1. Tardigrade
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  3. Physics
  4. A stuntman plans to run across a rooftop and then horizontally off it to land on the roof of the next building. The roof of the next building is 4.9 m below the first one and 6.2 m away from it. What should be his minimum speed, in m/s, so that he can successfully make the jump

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Q. A stuntman plans to run across a rooftop and then horizontally off it to land on the roof of the next building. The roof of the next building is 4.9 m below the first one and 6.2 m away from it. What should be his minimum speed, in m/s, so that he can successfully make the jump

AMUAMU 1996

Solution:

: Vertical height = 4.9 m $ \therefore $ $ h=ut+\frac{1}{2}g{{t}^{2}} $
or $ 4.9=0+\frac{1}{2}\times 9.8{{t}^{2}} $ or $ 4.9{{t}^{2}}=4.9 $ or $ {{t}^{2}}=1 $ or $ t=1\text{ }sec $ Horizontal velocity $ =v $ $ \therefore $ Range= 6.2 m; $ \therefore $ $ v\times time=6.2 $ or $ v\times 1=6.2 $ or $ v=6.2\text{ }m/s $

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