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Q. A string of length L and mass M hangs freely from a fixed point. Then, the velocity of transverse waves along the string at a distance $ x $ from the free end is

Jharkhand CECEJharkhand CECE 2012

Solution:

Total length of string = L Mass of the string = M
The velocity of transverse wave
$ v=\sqrt{\frac{T}{m}} $
where, $ T= $ weight of part of string hanging below the point under consideration
$ =\left( \frac{M}{L1} \right)xg $
$ \Rightarrow $ $ v=\sqrt{\frac{\left( \frac{M}{L} \right)xg}{\left( \frac{M}{L} \right)}}=\sqrt{xg} $

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