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Q. A stretched string of length $ l, $ fixed at both ends can sustain stationary waves of wavelength given by

Rajasthan PETRajasthan PET 2003

Solution:

$ \lambda =\frac{2l}{n}, $
where $ n= $ number of loops.
at $ n=1 $ $ \lambda =2l $ at $ n=2 $
$ \lambda =\frac{2l}{2} $ at $ n=3 $
$ \lambda =\frac{2l}{3} $ at $ n=n $
$ \lambda =\frac{2l}{n} $

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