Q. A stretched string of length $ l, $ fixed at both ends can sustain stationary waves of wavelength given by
Rajasthan PETRajasthan PET 2003
Solution:
$ \lambda =\frac{2l}{n}, $
where $ n= $ number of loops.
at
$ n=1 $ $ \lambda =2l $ at $ n=2 $
$ \lambda =\frac{2l}{2} $ at $ n=3 $
$ \lambda =\frac{2l}{3} $ at $ n=n $
$ \lambda =\frac{2l}{n} $
