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  4. A stretched string is 1 m long. Its mass per unit length is 0.5 g / m. It is stretched with a force of 20 N. It plucked at a distance of 25 cm from one end. The frequency of note emitted by it will be :

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Q. A stretched string is $1\, m$ long. Its mass per unit length is $0.5\, g / m$. It is stretched with a force of $20\, N$. It plucked at a distance of $25\, cm$ from one end. The frequency of note emitted by it will be :

Haryana PMTHaryana PMT 2003

Solution:

Using relation $f=\frac{p}{2 l} \sqrt{\frac{T}{m}}$
(Since, string is plucked at $25\, cm$ hence, it will vibrate in two segments $p=2$ ) $f=\frac{2}{2 \times 1} \sqrt{\frac{20}{0.5 \times 10^{-3}}}$
$=200\, Hz$