Q. A straight line through P (1, 2) is such that its intercept between the axes is bisected at P. Its equation is:
KEAMKEAM 2003
Solution:
$ \because $ P (1, 2) is midpoint of AB, therefore co-ordinate of A and B respectively (2, 0) and (0, 4)
$ \therefore $ Equation of line AB is $ y-0=\frac{4}{-2}(x-4) $ $ \Rightarrow $ $ 2x+y=8 $
