1. Tardigrade
  2. Question
  3. Physics
  4. A straight conductor carrying a current I splits into two identical semicircular arcs as shown in figure below. What is the magnitude of the magnetic field at the center C of the resulting circular arcs of radius R?

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Q. A straight conductor carrying a current $I$ splits into two identical semicircular arcs as shown in figure below. What is the magnitude of the magnetic field at the center $C$ of the resulting circular arcs of radius $R$?Physics Question Image

AMUAMU 2015Moving Charges and Magnetism

Solution:

Magnetic field due to BAC arc is
$B=\frac{\mu_{0} \pi(I / 2)}{4 \pi R} \otimes$ ... (i)
Magnetic field due to $ADC$ are is
$B=\frac{\mu_{0} \pi(I / 2)}{4 \pi R}$ ... (ii) F
rom Eqs. (i) and (ii) n
et magnetic field is zero.

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