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Q. A stone tied to a string is rotated with a uniform speed in a vertical plane. If mass of the stone is $m$, length of the string is $r$ and linear speed of the stone is $v$, then tension in the string when the stone is at its lowest point is

Laws of Motion

Solution:

We know that centrifugal force $=mv^{2}/r$
When the stone is at the lowest point, then Tension in string = centrifugal force + weight of stone
$\therefore T=\frac{mv^{2}}{r}+mg$