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Q. A stone thrown vertically upwards with a speed of 5 m/sec attains a height $H_1$. Another stone thrown upwards from the same point with a speed of 10 m/sec attains a height $H_2$. The correct relation between $H_1$ and $H_2$ is

Motion in a Straight Line

Solution:

From third equation of motion $v^2 = u^2 + 2ah $
In first case initial velocity $u_1 = 5 \, m/ \sec$
final velocity $v_1 = 0, a = - g$
and max. height obtained is $H_1$, then,
$H_1 = \frac{25}{2g}$
In second case $u_2 = 10 \, m/ \sec, v_2 = 0, a = -g$
and max. height is $H_2$ then, $H_2 = \frac{100}{2g}$
It implies that $H_2 = 4H_1$