1. Tardigrade
  2. Question
  3. Physics
  4. A stone thrown vertically upwards attains a maximum height of 45 m. In what time the velocity of stone become equal to one-half the velocity of throw? (. Given g=10 ms -2 )

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Q. A stone thrown vertically upwards attains a maximum height of $45 \,m$. In what time the velocity of stone become equal to one-half the velocity of throw? $\left(\right.$ Given $g=10 \,ms ^{-2}$ )

Motion in a Straight Line

Solution:

Let us solve the problem in terms of relative initial velocity, relative acceleration and relative displacement of the coin with respect to floor of the lift.
Given, $u=0 \,ms ^{-1}, a =9.8 \,ms ^{-2}, s =4.9 \,m , t=?$
As, $4.9=0 \times t+\frac{1}{2} \times 9.8 \times t^{2}$
Or $4.9 \,t^{2}=4.9$
Or $t=1 \,s$
or $15 =30-10 \,t $
$ 10\,t =15 $
Or $t=1.5 \,s$