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Q. A stone thrown upward with a speed $u$ from the top of the tower, reaches the ground with velocity $3u$. The height of the tower is

Rajasthan PETRajasthan PET 2003

Solution:

$ {{v}^{2}}={{u}^{2}}+2gh $ or $ {{(3u)}^{2}}={{u}^{2}}+2gh $ or $ h=\frac{4{{u}^{2}}}{g} $