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Q. A stone of mass $m$ tied to the end of a string revolves in a vertical circle of radius $R$. The net forces at the lowest and highest points of the circle directed vertically downwards are
Lowest Point Highest Point
(a) $mg-T_{1}$ $mg+T_{2}$
(b) $mg +T_{1}$ $mg-T_{2}$
(c) $mg+T_{1}$ $-\left(\frac{mv_{1}^{2}}{R}\right)$ $mg-T_{2}$ $+\left(\frac{mv_{2}^{2}}{R}\right)$
(d) $mg-T_{1}$ $-\left(\frac{mv_{1}^{2}}{R}\right)$ $mg+T_{2}$ $+\left(\frac{mv_{2}^{2}}{R}\right)$


$T_{1}$ and $v_{1}$ denote the tension and speed at the lowest point. $T_{2}$ and $v_{2}$ denote corresponding values at the highest point.

Laws of Motion

Solution:

At the lowest point, mg acts downwards and $T_{1}$
upwards so that net force $=mg$ $-T_{1}$.
At the highest point, both $mg$ and $T_{2}$ act downwards so that net force$=mg$ $+T_{2}.$