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Q. A stone of mass $1 \, kg$ tied to the end of a string of length $1 \, m$ , is whirled in a horizontal circle with a uniform angular velocity $2 \, rad \, s^{- 1}$ . The tension of the string is (in newton)

NTA AbhyasNTA Abhyas 2022

Solution:

Tension in string will provide required centripetal force.
The tension of the string,
$T=mr\omega ^{2}$
$=1\times 1\times \left(\right. 2 \left.\right)^{2}=4 \, N$