1. Tardigrade
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  3. Physics
  4. A stone of mass 1 kg is tied at one end of a string of length 1 m . It is whirled in a vertical circle at a constant speed of 4 m s- 1 . The tension in the string is 6 N when the stone is at (.g=10 m s- 2.)

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Q. A stone of mass $1 \, kg$ is tied at one end of a string of length $1 \, m$ . It is whirled in a vertical circle at a constant speed of $4 \, m \, s^{- 1}$ . The tension in the string is $6 \, N$ when the stone is at $\left(\right.g=10 \, m \, s^{- 2}\left.\right)$

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

When the string makes an angle $\theta $ with the vertical, then
$T-mgcos\theta =\frac{m v^{2}}{r}$
Substituting the values, we obtain
$6 - \left(1\right) \left(1 0\right) \text{cos} \theta = \frac{4^{2} \text{.} 1}{1}$ = 16
$\text{cos} \theta = - 1$
$\theta = 1 8 0^{\text{o}}$