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Q. A stone of mass $0.3kg$ attached to a $1.5m$ long string is whirled around in a horizontal circle at a speed of $6ms^{- 1}$ . The tension in the string is

NTA AbhyasNTA Abhyas 2022

Solution:

The force of tension in the string provides required centripetal force to keep the stone in circular motion.
$\therefore T=\frac{m v^2}{R}=\frac{0.3 \times(6)^2}{1.5}=7.2 N$