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  4. A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

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Q. A stone of mass $0.05 \,kg$ is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

J & K CETJ & K CET 2014Laws of Motion

Solution:

Given, $m = 0.05\, kg $
We know that, net force acting on a stone,
$f_{g}=mg$
$= 0.05 \times (-9.8)=-0.40\,N$
$ = 0.49 \,N$ vertically downwards