Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A stone is projected at angle $30^{\circ}$ to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be -

JEE MainJEE Main 2023Work, Energy and Power

Solution:

$\frac{ KE _{ POP }}{ KE _{\text {top }}}=\frac{\frac{1}{2} M ( u )^2}{\frac{1}{2} M \left( u \cos 30^{\circ}\right)^2}=\frac{4}{3}$