1. Tardigrade
  2. Question
  3. Physics
  4. A stone is dropped into water from a bridge 44.1 m above the water. Another stone is thrown vertically downward 1 sec later. Both strike the water simultaneously. What was the initial speed of the second stone

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Q. A stone is dropped into water from a bridge $44.1\, m$ above the water. Another stone is thrown vertically downward $1$ sec later. Both strike the water simultaneously. What was the initial speed of the second stone

Motion in a Straight Line

Solution:

For the first stone $t=\sqrt{\frac{2 h}{g}}$
$=\sqrt{\frac{2 \times 44.1}{9.8}}=3 $ Sec
Time left for second stone $=3-1=2$ Sec
Hence $44.1=u \times 2+\frac{1}{2} 9.8(2)^{2}$
$\Rightarrow 44.1-19.6=2 u$
$ \Rightarrow u=12.25\, m / s$