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  4. A stone falls from a balloon that is descending at a uniform rate of 12 m/s. The displacement of the stone from the point of release after 10 s is

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Q. A stone falls from a balloon that is descending at a uniform rate of $12\, m/s.$ The displacement of the stone from the point of release after $10\, s$ is

Solution:

$u=12\, m / s ,\, g =9.8\, \,m / s ^{2}, t=10\, s$
Displacement $=u t+\frac{1}{2} g t^{2}$
$=12 \times 10+\frac{1}{2} \times 9.8 \times 100=610\, \,m .$