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  4. A stone falls freely from rest from a height h and it travels a distance (9h/25) in the last second. The value of h is

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Q. A stone falls freely from rest from a height $h$ and it travels a distance $\frac{9h}{25}$ in the last second. The value of $h$ is

KEAMKEAM 2011Gravitation

Solution:

$\frac{9h}{25}=\frac{g}{2}(2t-1)$
$\frac{1}{2}gt^2=h$
h = 122.5 m