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Physics
A step-down transformer with an efficiency of 80 % is used on a 1000 V line to deliver 10 A at 100 V at the secondary coil. The current drawn from the line is
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Q. A step-down transformer with an efficiency of $80\, %$ is used on a $1000\, V$ line to deliver $10\, A$ at $100\, V$ at the secondary coil. The current drawn from the line is
KEAM
KEAM 2013
Alternating Current
A
1.5 A
0%
B
2 A
27%
C
3 A
27%
D
1.25 A
45%
E
1 A
45%
Solution:
Given, $ \eta=80 \%, \, V_{\text {in }}=1000\, V ,\, l=10 \,A$ and
$V=100\, V$
Output power
$P_{\text {out }}=I \times V$
$P_{\text {out }}=10 \times 100$
$ P_{\text {out }} =1000 \,VA $
and $P_{\text {in }} =\frac{P_{\text {out }}}{\eta}=\frac{1000}{0.8} \,VA $
$ I_{\text {in }} =\frac{P_{\text {in }}}{V_{\text {in }}}=\frac{1000}{0.8 \times 1000}$
$I_{\text {in }} =1.25\, A$