Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A step down transformer is connected to 2400 volts line and 80 amperes of current is found to flow in output load. The ratio of the turns in primary and secondary coil is 20 : 1. If transformer efficiency is 100%, then the current flowing in the primary coil will be

Alternating Current

Solution:

$\frac{N_{s}}{N_{p}}=\frac{V_{s}}{V_{p} \Rightarrow \frac{1}{20}=\frac{V_{s}}{2400} \Rightarrow V_{s}=120 V}$
For $100 \%$ efficiency $V_{s} i_{s}=V_{p} i_{p}$
$\Rightarrow 120 \times 80=2400 i_{p} \Rightarrow i p=4 A$