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Q. A step down transformer converts transmission line voltage from $11000\,V$ to $220\,V$. The primary of the transformer has $6000$ turns and efficiency of the transformer is $60\, \%$. If the output power is $9\,kW$, then the input power will be

Alternating Current

Solution:

Here,
$V_p=11000\,V$,
$V_s = 220\,V$
$N_p = 6000$,
$\eta = 60\%;$
$P_0 = 9\,kW = 9 \times 10^3\,W$
Efficiency, $\eta=\frac{Output \,power}{Input\, power}=\frac{P_{o}}{P_{i}}$
$\therefore P_{i}=\frac{P_{o}}{\eta}$
$=\frac{9\times10^{3}}{60 / 100 }$
$=1.5\times10^{4}
=15\,kW$