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Q. A stationary nucleus disintegrates suddenly in two nuclei $X$ and $Y$ . The ratio of the kinetic energy of the two nuclei $X$ and $Y$ after the disintegration is $1:2$ , the ratio of the radii of the nuclei $X$ and $Y$ will be

NTA AbhyasNTA Abhyas 2020

Solution:

$\frac{k_{x}}{k_{y}}=\frac{p_{x}^{2} / 2 m_{x}}{p_{y}^{2} / 2 m_{y}}=\frac{m_{y}}{m_{x}}=\frac{1}{2}$
$\frac{r_{x}}{r_{y}}=\left(\frac{A_{x}}{A_{y}}\right)^{1 / 3}=\left(\frac{m_{x}}{m_{y}}\right)^{1 / 3}=2^{1 / 3}$