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  4. A standing wave propagating with velocity 300 m/s-1 in an open pipe of length 4 m has four nodes. The frequency of the wave is

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Q. A standing wave propagating with velocity $300\, m/s^{-1}$ in an open pipe of length $4\, m$ has four nodes. The frequency of the wave is

KEAMKEAM 2017Waves

Solution:

image
Nodes are produced in the open pipe as shown in figure.
So,$2 \lambda=4$
$\lambda=\frac{4}{2}=2 \,m$
From wave equation,
$V =n \lambda $
$n =\frac{V}{\lambda} $
$=\frac{300}{2} $
$=150\, Hz$