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Q. A square wire frame of side a is placed a distance b away from a long straight conductor carrying current I. The frame has resistance R and self-inductance L. The frame is rotated by $180^{o}$ about OO' as shown in Fig. Find the electric charge flown through the frame -

Question

NTA AbhyasNTA Abhyas 2020

Solution:

$i=\frac{1}{R}\left[\frac{d \phi}{d t} + L \frac{d i}{d t}\right]$
$q=\displaystyle \int i d t=\frac{1}{R}\left[\Delta \phi + 0\right]=\frac{\Delta \phi}{R}=\frac{1}{R}\displaystyle \int _{b - a}^{b + a} B a d x$
$=\frac{1}{R}\displaystyle \int _{b - a}^{b + a} \frac{\mu _{0} i a}{2 \pi x}dx=\frac{\mu _{0} i a}{2 \pi R}log_{e} \frac{b + a}{b - a}$