Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A square loop of wire of each side 50 cm is kept, so that its plane makes an angle 9 with a uniform magnetic field of induction 1 T. The magnetic field is withdrawn in 0.1 s. It is found that the induced emf across the loop is 125 mV. The angle 0 is

VMMC MedicalVMMC Medical 2011

Solution:

$ e=nAB\sin ({{90}^{o}}-\theta ) $ $ =nAB\cos \theta $ $ \therefore $ $ 125\times {{10}^{-3}}=1\times 0.5\times 0.5\times 1\times \cos \theta $ $ \cos \theta =\frac{1}{2} $ $ \theta ={{60}^{o}} $