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Q. A square loop of side a hangs from an insulating hanger of spring balance. The magnetic field of strength $B$ occurs only at the lower edge. It carries a current $I$. Find the change in the reading of the spring balance if the direction of current is reversed.Physics Question Image

Moving Charges and Magnetism

Solution:

Initially $F_{1}+m g+I a B$ (downwards)
When the direction of current is reversed
$F_{2}=m g=-I a B $ (downwards)
$ \Rightarrow \Delta F=2 I a B$