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  4. A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is F, the net force on the remaining three arms of the loop is:

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Q. A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is $F$, the net force on the remaining three arms of the loop is:

Moving Charges and Magnetism

Solution:

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Forces, $F_{1}$ and $F_{2}$ acting on the coil are equal in magnitude and opposite in directions. As the forces $F _{1}$ and $F _{2}$ have the same line of action, their resultant effect on the coil is zero.
$\tau=N i B A \sin \theta$
$\tau_{\max }=\operatorname{NiBA}\left(\theta=90^{0}\right)$
The two forces $F_{3}$ and $F_{4}$ are equal in magnitude and opposite in direction. As the two forces have different lines of action, they constitute a torque. Thus, if the force on one arm of the loop is $F$, the net force on the remaining three arms of the loop is $-F$.