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Physics
A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is :
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Q. A spring is stretched by $5\, cm$ by a force $10\, N$. The time period of the oscillations when a mass of $2\, kg$ is suspended by it is :
NEET
NEET 2021
Oscillations
A
0.0628 s
19%
B
6.28 s
31%
C
3.14 s
6%
D
0.628 s
44%
Solution:
$K =\frac{10}{5 \times 10^{-2}} N / m =200 N / m$
$\therefore T =2 \pi \sqrt{\frac{ m }{ K }}=2 \pi \sqrt{\frac{2}{200}} s =\frac{\pi}{5} s$
$T =0.628 \,s$