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Q. A spring is compressed between two toy carts of mass $m_1$ and $m_2$. When the toy carts are released, the springs exert equal and opposite average forces for the same time on each toy cart. If $V_1$ and $V_2$ are the velocities of the toy carts and there is no friction between the toy carts and the ground, then :

BITSATBITSAT 2010

Solution:

Here, $m_{1} \frac{d V_{1}}{d t}=-m_{2} \frac{d V_{2}}{d t}$
or $m_{1} a_{1}=m_{2} a_{2} \ldots$ (1)
now, $V_{1}=a_{1} t$ and $V_{2}=a_{2} t$ (by using $v=u+$ at)
from (1), $m _{1} \frac{ V _{1}}{ t }=- m _{2} \frac{ V _{2}}{ t }$
$\therefore \frac{ V _{1}}{ V _{2}}=-\frac{ m _{2}}{ m _{1}}$