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  4. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m/s2, the reading of the spring balance will be

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Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $ 5\,m/{{s}^{2}}, $ the reading of the spring balance will be

Rajasthan PMTRajasthan PMT 2008Laws of Motion

Solution:

In stationary position, spring balance reading
$ =mg=49 $ $ m=\frac{4.9}{9.8}=5\,\,kg $ When lift moves downward. $ mg-T=ma $ Reading of balance $ T=mg-ma $ $ =5(9.8-5) $ $ =5\times 4.8 $ $ =24\,\,N $

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