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  4. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m s-2, the reading of the spring balance will be

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Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $ 5 \, m\, s^{-2}$, the reading of the spring balance will be

JIPMERJIPMER 2012Laws of Motion

Solution:

When lift is stationary, $W_1 = mg$
When the lift descends with acceleration $a$ ,
$W_2 = m (g - a)$
$\therefore \, \frac{W_2}{W_1} = \frac{m(g - a)}{mg} = \frac{9.8 - 5}{9.8} = \frac{4.8}{9.8}$
or $W_2 = W_1 \times \frac{4.8}{9.8} = \frac{49 \times 4.8}{9.8} = 24 \, N$