Q. A spring balance carries a load. When the load is pulled aside so that the balance makes an angle of $30^{\circ}$ with the vertical, the balance reads $4 \, kg\, wt$. The mass of the load is
Solution:
$F_x =$ reading in spring balance
= 4 kg wt
From figure, $F_x \cos 30^{\circ} = mg$
(4 kg wt) $\frac{\sqrt{3}}{2} $ = mg
So, $m = 2 \sqrt{3}$ kg