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Q.
A spherical mirror forms an image of magnification $3 .$ The object distance, if focal length of mirror is $24\,cm$, may be
Ray Optics and Optical Instruments
Solution:
$m=\frac{f}{f-u}$
$3=\frac{-24}{-24-u} $ or $-24-u=-8$ or $u+24=8$
or $u=(8-24) \,cm =-16\,cm$
If $m=-3$, then $;-3=\frac{-24}{-24-u} u+24=-8$
or $u=-32 \,cm$.