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Q. A spherical drop of water has radius $1 \, mm$ If the surface tension of water is $70\times 10^{- 3} \, N \, m^{- 1}$ . Difference of pressures between inside and outside of the spherical drop is

NTA AbhyasNTA Abhyas 2020

Solution:

$\Delta P=\frac{2 T}{R}=\frac{2 \times 70 \times 10^{- 3}}{1 \times 10^{- 3}}=140N\text{​ }m^{- 2}$