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Q. A spherical conductor of radius $2\, m$ is charged to a potential of $120\, V$. It is now placed inside another hollow spherical conductor of radius $6\, m .$ Calculate the potential to which the bigger sphere would be raised.

Electrostatic Potential and Capacitance

Solution:

If charge acquired by the smaller sphere is $Q$, then its potential
$120=\frac{k Q}{2}$ ...(i)
Also, potential of the outer sphere
$V=\frac{k Q}{6}$ ...(ii)
From equations (i) and (ii),
$V=40$ volt