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Q. A sphere is suspended by a thread of length $l$ . The minimum horizontal velocity which has to be imparted to the sphere for it to reach the height of suspension is

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Kinetic energy at $A=\frac{1}{2}mu^{2}$
Potential energy at $B=mgh$
For conservation of energy, $\frac{1}{2}mu^{2}=mgl$
$u=\sqrt{2 g l}$