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  4. A source and an observer moves away from each other, with a velocity of 15 m/s with respect to ground. If observer finds the frequency of sound coming from source as 1950 Hz. Then actual frequency of source will be (velocity of sound = 340 m/s):

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Q. A source and an observer moves away from each other, with a velocity of 15 m/s with respect to ground. If observer finds the frequency of sound coming from source as 1950 Hz. Then actual frequency of source will be (velocity of sound = 340 m/s):

BVP MedicalBVP Medical 2002

Solution:

Apparent frequency $ n=n\frac{\upsilon -{{\upsilon }_{0}}}{\upsilon +{{\upsilon }_{s}}} $ where, $ {{\upsilon }_{0}} $ = speed of observer $ {{\upsilon }_{s}} $ = speed of source, $ \upsilon $ = speed of sound, n = actual frequency $ \therefore $ $ 1950=n\frac{340-15}{340+15} $ $ n=\frac{1950\times 355}{325}=2130Hz $