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Q.
A sonometer wire of length $114\, cm$ is fixed at both the ends. Where should the two bridges be placed so as to divide the wire into three segments whose fundamental frequencies are in the ratio $1 : 3 : 4$ ?
Total length of the wire, $L = 114\, cm$
$n_2: n_2 : n_3 = 1 :3 :4$
Let $L_1, L_2$ and $L_3$ be the lengths of the three
As $n\,\propto \frac{1}{L}$
$\therefore L_{1} : L_{2} : L_{3}=\frac{1}{1} : \frac{1}{3} : \frac{1}{4}=12 : 4 : 3$
$\therefore L_{1}=72\,cm\left(\frac{12}{12+4+3}\times114\right)$
$L_{2}=24\,cm\left(\frac{4}{19}\times114\right)$
and $L_{3}=18\,cm\left(\frac{3}{19}\times114\right)$
Hence the bridges should be placed at $72\, cm$ and $72 + 24 = 96\, cm$ from one end. parts