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Q. A solution of weak acid $HA$ is being titrated with $0.1\, M$ $NaOH$ solution. End point is reached on addition of $x \,mL$ of $NaOH$. To the above solution, $\frac{x}{2} mL$ of $0.10\, M$ $HCl$ is added further. $pH$ of the resulting solution was found to be $5.3$. Determine $pH$ at the end point if initial concentration of weak acid was $0.10\, M$.

Equilibrium

Solution:

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$pH = pK _{ a }+\log \frac{\left[ A ^{-}\right]}{[ HA ]}= pK _{ a }=5.3$
$ \Rightarrow K _{ a }=5 \times 10^{-6}$
$A ^{-}+ H _{2} O \rightleftharpoons HA + OH ^{-}$
$K _{ a }= K _{ a }=\frac{ k _{ w }}{ k _{ a }}=2 \times 10^{-9}$
$\Rightarrow\left[ OH ^{-}\right]=\sqrt{ K _{ h } C }$
$=\sqrt{2 \times 10^{-9} \times 0.05}=10^{-8}$
$\Rightarrow pOH =5$ and $pH =9$